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Determine whether an integer is a palindrome. Do this without extra space.
Could negative integers be palindromes? (ie, -1)
If you are thinking of converting the integer to string, note the restriction of using extra space.
You could also try reversing an integer. However, if you have solved the problem "Reverse Integer", you know that the reversed integer might overflow. How would you handle such case?
There is a more generic way of solving this problem.
代码:
class Solution(object): def isPalindrome(self, x): """ :type x: int :rtype: bool """ if x<0: return False if x<2**31: x = str(x) xlength = len(x)/2 n = -1 for a in range(xlength): if x[a]!=x[n]: return False n = n-1 return True return False代码测试花费的时间有点长,应该有更好的方法,若有想法,请指出,谢谢
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